Odd and Even using if condition in python


Odd and Even using if condition in python

Odd and Even by using def in Python way–>1

def odd_even(num):
    odd=[]
    even=[]
    for i in num:
        if i%2 == 0:
            even.append(i)
        else:
            odd.append(i)
    output_num=[odd,even]
    return output_num
number=[1,2,3,12,15,6,7,8,9]
print(odd_even(number))

Odd and Even by using def and if way–>2

def odd_even(num):

    if num%2==0:
        return "even"    else:
        return "odd"number=int(inPut("enter any number:"))
print(odd_even(12))

Odd and Even By using def in Python way —–>3

 
def odd_even(num):
    if num%2==0:
        return "even"    
    return "odd"
numb=input("enter any no:")
print(odd_even(numb))

Odd and even in Python way—>4

def odd_even(num):
    if num%2==0:
        return True
    return False
print(odd_even(112))
 

Check is Even or not in Python shortcut way—>5

 
def is_even(num):
    return num%2==0
print(is_even(11))

Odd and Even using if condition in python

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