# Odd and Even using if condition in python

### Odd and Even by using def in Python way–>1

```def odd_even(num):
odd=[]
even=[]
for i in num:
if i%2 == 0:
even.append(i)
else:
odd.append(i)
output_num=[odd,even]
return output_num
number=[1,2,3,12,15,6,7,8,9]
print(odd_even(number))```

## Odd and Even by using def and if way–>2

### def odd_even(num):

```    if num%2==0:
return "even"    else:
return "odd"number=int(inPut("enter any number:"))```
`print(odd_even(12))`

### Odd and Even By using def in Python way —–>3

```def odd_even(num):
if num%2==0:
return "even"    ```
`    return "odd"`
`numb=input("enter any no:")`
`print(odd_even(numb))`

### Odd and even in Python way—>4

```def odd_even(num):
if num%2==0:
return True```
`    return False`
`print(odd_even(112))`
` `

### Check is Even or not in Python shortcut way—>5

` `
```def is_even(num):
return num%2==0```
`print(is_even(11))`

### Have any Question or Comment?

#### One comment on “Odd and Even using if condition in python”

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